Mathematics Applied to Action Scene

Today what I am going to share is an easy mathematical calculation which reveals a surprising fact; this thought came into my mind just yesterday while I as drinking tea standing in a tea stall and some customers arrived there in their bikes.

We all know that there are lots of fictitious things are shown in many movies, like…the villain flies in the sky and travels 10ft-20ft after getting a kick from the hero, sometime heroes holds the legs of villains and throws him as we can throw cricket bats, this is the reason in the beginning of the movies you can see the preface…”all these characters are fictitious…..”

Now let me tell you what I am going to share today…

I am going to calculate the weights (approx.) of the heroes from action movies…

The scene is...a villain in a bike comes towards the hero with the intention to hit the hero with his fast moving bike, hero doe not move from his position and standing still the hero lifts his one leg kicks the front portion of the moving bike and receiving kick from the hero the rider fell along with the bike in the same direction that he was coming.

This is a very common scene we have watched in many movies, so now my calculation is….

The average weight of a bike is 100kg.

The average weight of a villain is 60 kg

Total weight is  =  160kg.

The speed of the bike is 40km/hr = 11.11m/s

Then the momentum (mass × velocity) of the system (Bike+Hero) is

 160 × 11.11 kg-m/s= 1777.6 Kg-m/s

To stop this momentum the equal or greater amount of momentum is needed, let me consider the force exerted by the kick of the hero is equal to this force, now the speed of the moving leg is hardly 2km/s means 5.55m/s, so what should be the weight of the leg…

Now equaling both sides

Weight of the leg ×  speed of leg  =  weight of the system× speed of the system

Putting the values we get…

Weight of the leg × 5.55m/s  =  160kg × 11.11 m/s

                                                     =1777.6 kg-m/s

Therefore, the weight of the leg  = 1777.6kg-m/s  ÷  5.55m/s

                                                        = 320kg 

 (m/s in up and down will cancel each other)

So this should be the weight of a leg of a hero (Lead character) who can stop a moving bike which weights 100kg and speed 40km/hr with a villain whose weight is 60kg.

If 320kg is the weight of one leg then try to guess what should be the weight of the whole body…I think approximately 1600kg.

This type of calculations are  actually done by “impulsive Force” theory of Physics, but don’t worry though I have made this one easier but it will not affect the calculation much.